2x^2+170x+86=0

Solution for 2x^2+170x+86=0 equation:

2x^2+170x+86=0

a = 2; b = 170; c = +86;
Δ = b2-4ac
Δ = 1702-4·2·86
Δ = 28212
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{28212}=\sqrt{4*7053}=\sqrt{4}*\sqrt{7053}=2\sqrt{7053}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(170)-2\sqrt{7053}}{2*2}=\frac{-170-2\sqrt{7053}}{4}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(170)+2\sqrt{7053}}{2*2}=\frac{-170+2\sqrt{7053}}{4}
$